Doing some HW and havn't done sample size stuff in a while.

We have standard deviation = 10
Mu (mean) = M = ?

Ok,


We want to find a large enough sample size (=N) that has a 95.44% confidence interval. Error Bound = 1.

So, N = ?


N >or= { [Z(alpha/2) squared] *[J(sigma or S) squared] } / B squared

N = [1.96 squared *10 squared] / 1 squared

N = [3.8416 * 100] / 1

N = 384.16


Is this correct?????

thanks for the help

 

2+2=5. I hate math that's why I'm not an accountant.

 

sorry. Its beeon at least 12 years since I did Stats at school.

I can remember X, X bar, Mu, standard deviations, but damned if I can remember how to use them.

 

Pie R Square (that's all the math I remember)

 

If my math class teaching that stuff wasn't at 8 in the morning during the college days, I might have stayed awake long enough to answer that question.