equation for displacement vs psi
#17
Originally posted by grinomyte
boost is determined by how fast the s/c so i dont think you can determine it until you know what pullies and what engine its gonna run on.
boost is determined by how fast the s/c so i dont think you can determine it until you know what pullies and what engine its gonna run on.
Take 2 Lightning motors for example:
1-stock heads, exhaust, cams, pistons, valves and a 4# lower........say it makes 12 psi.
2-ported heads, full exhaust, aftermarket pistons/valves and a 4# lower.........say it makes 10psi.
Ya follow brutha...........oh and I still don't know what the 8.8 is
--Joe
#19
Coldie is half right, its a little more involved. The temp of the air coming out of the intercooler is not ambient. So its not as dense as the air a NA engine of coldie's equations would be sucking in.
Lets take a 6lb for example:
(14.7+8+6)/14.7 = 1.95 thats the absolute pressure of the manifold. That puts us at 5.4L * 1.95 = 10.53L
Through the magic of physics we get that the temp of the air after the intercooler is about 145 degrees on a 80 degree day. The density of the air is (460+80)/(460+145)=.89
So we get an equivalent displacement of *drum roll*
9.37L
Soap,
An NA car could have better flowing heads, cams, etc to increase power without increasing displacement. This is all things being equal.
Lets take a 6lb for example:
(14.7+8+6)/14.7 = 1.95 thats the absolute pressure of the manifold. That puts us at 5.4L * 1.95 = 10.53L
Through the magic of physics we get that the temp of the air after the intercooler is about 145 degrees on a 80 degree day. The density of the air is (460+80)/(460+145)=.89
So we get an equivalent displacement of *drum roll*
9.37L
Soap,
An NA car could have better flowing heads, cams, etc to increase power without increasing displacement. This is all things being equal.
#20
Originally posted by Sublime
Coldie is half right, its a little more involved. The temp of the air coming out of the intercooler is not ambient. So its not as dense as the air a NA engine of coldie's equations would be sucking in.
Lets take a 6lb for example:
(14.7+8+6)/14.7 = 1.95 thats the absolute pressure of the manifold. That puts us at 5.4L * 1.95 = 10.53L
Through the magic of physics we get that the temp of the air after the intercooler is about 145 degrees on a 80 degree day. The density of the air is (460+80)/(460+145)=.89
So we get an equivalent displacement of *drum roll*
9.37L
Soap,
An NA car could have better flowing heads, cams, etc to increase power without increasing displacement. This is all things being equal.
Coldie is half right, its a little more involved. The temp of the air coming out of the intercooler is not ambient. So its not as dense as the air a NA engine of coldie's equations would be sucking in.
Lets take a 6lb for example:
(14.7+8+6)/14.7 = 1.95 thats the absolute pressure of the manifold. That puts us at 5.4L * 1.95 = 10.53L
Through the magic of physics we get that the temp of the air after the intercooler is about 145 degrees on a 80 degree day. The density of the air is (460+80)/(460+145)=.89
So we get an equivalent displacement of *drum roll*
9.37L
Soap,
An NA car could have better flowing heads, cams, etc to increase power without increasing displacement. This is all things being equal.
#21
Re: No no no...
Originally posted by Coldie
OK, here's the formula:
330 * ( (PSI boost+14.7)/14.7)
That will give you the best guess for a NA engine. Note that it isn't the same because the SC will use power, but it's as close as spitting distance will get you...
So:
Stock: 509 ci
4lb pulley: 599 ci
6lb pulley: 644 ci
10lb pulley: 734 ci
This is just a blind formula to compare air usage. It does not imply anything about power or torque curves.
Coldie
OK, here's the formula:
330 * ( (PSI boost+14.7)/14.7)
That will give you the best guess for a NA engine. Note that it isn't the same because the SC will use power, but it's as close as spitting distance will get you...
So:
Stock: 509 ci
4lb pulley: 599 ci
6lb pulley: 644 ci
10lb pulley: 734 ci
This is just a blind formula to compare air usage. It does not imply anything about power or torque curves.
Coldie
#22
#23
Originally posted by Tim Skelton
Why wouldn't you do a volumetric efficiency analysis? Measure the volumetric efficiency of the stock 5.4. Then measure it again with the supercharger and use the result to extrapolate the effective displacement? I'm no engineer, but it seems like this would give a reliable number.
Why wouldn't you do a volumetric efficiency analysis? Measure the volumetric efficiency of the stock 5.4. Then measure it again with the supercharger and use the result to extrapolate the effective displacement? I'm no engineer, but it seems like this would give a reliable number.
pressure ratio = (SC displacement * sc rpm * sc VE)/(engine displacement * engine rpm * engine VE)
It still doesn't take into account the density of the air.
#24
It's pointless...
The real question is: what is the point?
We can keep adding terms to get "more correct" but even then, it doesn't really matter.
The easiest thing to do would be to simply measure the MAF reading at an RPM and poof, you've got a theoretical displacement...
Still not sure what we are trying to figure out though.
Thanks to Sublime for throwing in the temperature info.
Coldie
We can keep adding terms to get "more correct" but even then, it doesn't really matter.
The easiest thing to do would be to simply measure the MAF reading at an RPM and poof, you've got a theoretical displacement...
Still not sure what we are trying to figure out though.
Thanks to Sublime for throwing in the temperature info.
Coldie
#25
#27